O W Θ Limits

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1. Show that n is in O(n2)

0 ≤ h(n) ≤ cg(n)    

0 ≤ n ≤ cn2

0/n2 ≤ n/n2 ≤ cn2/n2

0 ≤ 1/n ≤ c        with c=1 and n0=1 because 1/n → 0 as n→∞

2. Show that n3+n2= Ω(n2)

0 ≤ cg(n) ≤ h(n)
0 ≤ cn2 ≤ n3+n2
0/n2 ≤ cn2/n2 ≤ n3+n2/n2
0 ≤ c ≤ n+1
0 ≤ 2 ≤ 2        with c=2 and n0=1 

3. Show that ½n(n-1)= Ω(n2)

0 ≤ cΩg(n) ≤ h(n)
0 ≤ cΩn2 ≤ ½n(n-1) = ½n2-½n
0/n2 ≤ cΩn2/n2 ≤ (½n2-½n)/n2
0 ≤ cΩ ≤ ½-½/n
0 ≤ cΩ ≤ ½-1/2n         for cΩ=¼ > 0 and n0=2

4. Show that ½n(n-1)= O(n2)

0 ≤ h(n) ≤ cOg(n)
0 ≤ ½n(n-1) = ½n2-½n ≤ cOn2
0/n2 ≤ (½n2-½n)/n2 ≤ cOn2/n2
0 ≤ ½-½/n ≤ cO
0 ≤ ½-1/2n ≤ cO         for cO=½  and n0=1 because 1/2n → 0 as n→∞

5. Show that ½n(n-1)= Θ(n2)

We have shown:

½n(n-1)= Ω(n2) for cΩ=¼ > 0 and n0=2

¼n2 ≤ ½n(n-1)

½n(n-1)= O(n2) for cO=½  and n0=1

½n(n-1) ≤ ½n2

By definition of Θ:

cΩg(n) ≤ h(n) ≤ cOg(n)

¼n2 ≤ ½n(n-1) ≤ ½n2

½n(n-1)= Θ(n2) for cO=½, cΩ=¼ and n0=2