7.2 The
Ambiguous Case of the Law of Sines
Direct
Application of Law of Sines applies for SAA or ASA
If given
Case 2, SSA, then zero, one or two such triangles may exist, because SSA does
not prove congruence between two triangles.
If angle A
is acute, there are four possibilities
|
Number of Triangles |
Sketch |
Applying Law of Sines Leads to |
|
0 |
|
|
|
1 |
|
|
|
1 |
|
|
|
2 |
|
|
If angle A is
obtuse, there are two possible outcomes
|
Number of Triangles |
Sketch |
Applying Law of Sines Leads to |
|
0 |
|
|
|
1 |
|
|
Applying the Law of Sines
1. For any angle
of a triangle,
. If
, then
and the triangle is a
right triangle.
2.
(Supplementary angles have the same sine value.)
3. The smallest angle
is opposite the shortest side, the largest angle is opposite the longest side,
and the middle-valued angle is opposite the intermediate side. (assuming
the triangle has sides that are all of different lengths.)
Example
Solve triangle ABC if ![]()
Example
Solve triangle ABC if ![]()
Number of Triangles
Satisfying the Ambiguous Case (SSA)
Let sides a and b and angle A be given in triangle ABC.
(The law of sines can be used to calculate the value of sin B.)
1. If applying the
law of sines results in an equation having
, then
no
triangle satisfies the given conditions.
2. If
, then one triangle satisfies the given
conditions and
.
3. If
, then either one or two triangles satisfy the
given conditions.
a) If ![]()
b) Let
then a second triangle
exists.
In this case, use
in the second
triangle.
Outline the steps to
take to solve each triangle. Do not
actually solve the triangle.
1. ![]()
2. ![]()
3. ![]()
4. ![]()
5. ![]()
Example
Solve triangle ABC, given ![]()
Example
Without using the law of sines, explain why no triangle ABC
exists satisfying ![]()