Review Requirements for a Binomial Distribution
If
and
, then the binomial random variable is approximately normally distributed
with the mean and standard deviation of
and
Using a CONTINUOUS model to Approximate
a DISCRETE
WHEN TO USE -
#2
#4
#6
#8
Procedure for Normal Approximation to Binomial
Page 267, especially 5...9
Example
24% of people have answering machines. Sample 2500 households. What is the probability that more than 650 have answering machines.
P = 651+652+653+...+2499+2500
Test if Normal is appropriate
np = .24 X 2500 = 600
nq = .76 X 2500 = 1900
and both are greater than 5
= np
= 600
=
=21.4
P(N
> 650) =
P(x
> 650.5) =
P( z
>
#10 Use program
Test if Normal appropriate
#18 p = .66, n = 1000, Test if Normal appropriate
=
P(x > 699.5) =
P(z >
#22 p = .07, n = 250,
=
P(x < 4.5) =
P(z <
#28 p = .10, n = 50,
=
P(x > 1.5) =
P(z >
DISCUS THE "LANGUAGE" of these problems versus sections 5.2, 5.3, 5.4, and 5.5. No Mean and Standard Deviation are given ... probability or percentage given ... and we must compute mean and standard deviation. DON'T FORGET the continuity correction factor.