5.6  Normal Distribution as Approximation to Binomial Distribution

Review Requirements for a Binomial Distribution

Requirements:

If       and      , then the binomial random variable is approximately normally distributed with the mean and standard deviation of    and 

Using a CONTINUOUS  model to Approximate a DISCRETE
 

WHEN TO USE -

Continuity Correction Factor
    Must adjust for continuity correction  (text  pg. 271)
 

    #2
 
 
 
 
 
 

    #4
 
 
 
 
 

   #6
 
 
 
 
 

    #8
 
 
 
 
 

Procedure for Normal Approximation to Binomial
            Page 267, especially 5...9

Example

    24% of people have answering machines.  Sample 2500 households.  What is the probability that more than 650 have answering machines.

            P  =  651+652+653+...+2499+2500
 
 
 
 
 
 

        Test if Normal is appropriate

                np = .24 X 2500 = 600
                nq = .76 X 2500 = 1900
                    and both are greater than 5

 = np = 600 =                    =21.4

        P(N > 650)  =
 
        P(x  > 650.5) =

        P( >
 
 

#10       Use program

            Test if Normal appropriate
 
 
 

#18        p = .66,   n = 1000,    Test if Normal appropriate

 =

            P(x > 699.5) =

            P(z >
 
 
 
 

#22        p = .07,   n = 250,

    =

            P(x < 4.5) =

        P(z <
 
 

 
 

 
 

#28        p = .10,    n = 50,

  =

        P(x > 1.5)  =

    P(z >
 
 
 
 
 

DISCUS THE "LANGUAGE" of these problems versus sections 5.2, 5.3, 5.4, and 5.5.  No Mean and Standard Deviation are given  ...  probability or percentage given ... and we must compute mean and standard deviation.  DON'T FORGET the continuity correction factor.