Electrostatics Simulation J
The simulation shows a dipole (plus and minus charges of equal magnitude)
with the electric field vectors. When you start the simulation a small test
charge is released at the location you specify below (x=0, y=0 is the center
of the simulation). The dipole charges do not move but the test charge will
move according to the forces it "feels" (The force vector on the test charge
is shown). The simulation assumes the test charge is so small that it does
not affect the fields of the dipole.
- Start the charge at x=0, y=0. What happens? Describe why this happens.
- Start the charge at x=0, y=2. What is the relationship between the
direction the test charge travels and the electric field vectors when the
charge first starts to move?
- What is the relationship between the direction the test charge travels
and the electric field vectors after the charge has moved for a while?
- How does the direction of the force vector on the test charge relate
to the electric field vectors?
- Why does the charge not collide with the dipole in this case (why doesn't
the charge follow the field vectors)?