Electrostatics Simulation J

Description:

The simulation shows a dipole (plus and minus charges of equal magnitude) with the electric field vectors. When you start the simulation a small test charge is released at the location you specify below (x=0, y=0 is the center of the simulation). The dipole charges do not move but the test charge will move according to the forces it "feels" (The force vector on the test charge is shown). The simulation assumes the test charge is so small that it does not affect the fields of the dipole.

x=  y= 

Extra Credit:

  1. Start the charge at x=0, y=0. What happens? Describe why this happens. 
  2. Start the charge at x=0, y=2. What is the relationship between the direction the test charge travels and the electric field vectors when the charge first starts to move? 
  3. What is the relationship between the direction the test charge travels and the electric field vectors after the charge has moved for a while?
  4. How does the direction of the force vector on the test charge relate to the electric field vectors?
  5. Why does the charge not collide with the dipole in this case (why doesn't the charge follow the field vectors)?